7p^2-11p+4=0

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Solution for 7p^2-11p+4=0 equation: 



7p^2-11p+4=0

a = 7; b = -11; c = +4;
Δ = b2-4ac
Δ = -112-4·7·4
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$


$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-3}{2*7}=\frac{8}{14}
=4/7
$


$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+3}{2*7}=\frac{14}{14}
=1
$

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